Which among the following is a paramagnetic complex :

Question

Which among the following is a paramagnetic complex : (A) [Co(NH3)6]3+ (B) [Pt(en)Cl2] (C) [CoBr4]2- (D) Mo(CO)6 (At. No. Mo = 42, Pt = 78)

Tardigrade Admin · Accepted Answer

Co 2+=(3 d 5) Bromine is a weak ligand but it is known that all tetrahedral complexes are high-spin regardless of the splitting power of the ligand. The low spin arrangement has five unpaired electrons in the d-orbital. So it is paramagnetic in nature.

Q. Which among the following is a paramagnetic complex :

$[C o (N H_{3})_{6}]^{3 +}$

$[Pt (e n) C l_{2}]$

$[C o B r_{4}]^{2 -}$

$M o (CO)_{6}$
(At. No. Mo = 42, Pt = 78)

$C o^{2 +} = (3 d^{5})$
Bromine is a weak ligand but it is known that all tetrahedral complexes are high-spin regardless of the splitting power of the ligand.
The low spin arrangement has five unpaired electrons in the d-orbital.
So it is paramagnetic in nature.

Q. Which among the following is a paramagnetic complex :

[Co(NH3​)6​]3+

[Pt(en)Cl2​]

[CoBr4​]2−

Mo(CO)6​ (At. No. Mo = 42, Pt = 78)

Co2+=(3d5) Bromine is a weak ligand but it is known that all tetrahedral complexes are high-spin regardless of the splitting power of the ligand. The low spin arrangement has five unpaired electrons in the d-orbital. So it is paramagnetic in nature.

$[C o (N H_{3})_{6}]^{3 +}$

$[Pt (e n) C l_{2}]$

$[C o B r_{4}]^{2 -}$

$M o (CO)_{6}$
(At. No. Mo = 42, Pt = 78)

$C o^{2 +} = (3 d^{5})$
Bromine is a weak ligand but it is known that all tetrahedral complexes are high-spin regardless of the splitting power of the ligand.
The low spin arrangement has five unpaired electrons in the d-orbital.
So it is paramagnetic in nature.