When water is heated from 0° C to 4° C and C p and C v are its specific heats at constant pressure and constant volume respectively, then :

Question

When water is heated from 0° C to 4° C and C p and C v are its specific heats at constant pressure and constant volume respectively, then : (A) C p > C v  (B) Cp < Cv (C) C p = C v  (D) Cp-Cv=R

Tardigrade Admin · Accepted Answer

When water is heated from 0° C to 4° C, its volume decreases. ∴ P Δ V is negative, hence C p - C v <0 or C p < C v

Q. When water is heated from $0^{\circ} C$ to $4^{\circ} C$ and $C_{p}$ and $C_{v}$ are its specific heats at constant pressure and constant volume respectively, then :

$C_{p} > C_{v}$

$C_{p} < C_{v}$

$C_{p} = C_{v}$

$C_{p} - C_{v} = R$

When water is heated from $0^{\circ} C$ to $4^{\circ} C$ , its volume decreases. $∴ P Δ V$ is negative,
hence $C_{p} - C_{v} < 0$ or $C_{p} < C_{v}$

Q. When water is heated from 0∘C to 4∘C and Cp​ and Cv​ are its specific heats at constant pressure and constant volume respectively, then :

Cp​>Cv​

Cp​<Cv​

Cp​=Cv​

Cp​−Cv​=R