When the temperature of a gas filled in a closed vessel is increased by 1 °C, its pressure increases by 0.4 percent. The initial temperature of gas was

Question

When the temperature of a gas filled in a closed vessel is increased by 1 °C, its pressure increases by 0.4 percent. The initial temperature of gas was (A)  250 °C (B)  25 °C (C) 250 K (D) 25 K

Tardigrade Admin · Accepted Answer

Using, PV = nRT Since volume is constant ∴ (P2/P1) = (T2/T1) or T1 = T2 × (P1/P2) or T1 =(T1 +1) ((100/100.4)) ⇒ T1 = 250 K

Q. When the temperature of a gas filled in a closed vessel is increased by $1^{\circ} C$ , its pressure increases by $0.4$ percent. The initial temperature of gas was

$250^{\circ} C$

$25^{\circ} C$

$250 K$

$25 K$

Using, $P V = n RT$
Since volume is constant
$∴ \frac{P _{2}}{P _{1}} = \frac{T _{2}}{T _{1}}$ or $T_{1} = T_{2} \times \frac{P _{1}}{P _{2}}$
or $T_{1} = (T_{1} + 1) (\frac{100}{100.4})$
$\Rightarrow T_{1} = 250 K$

Q. When the temperature of a gas filled in a closed vessel is increased by 1∘C, its pressure increases by 0.4 percent. The initial temperature of gas was

250∘C

25∘C

250K

25K