When the switch S, in the circuit shown, is closed, then the value of current i will be:

Question

When the switch S, in the circuit shown, is closed, then the value of current i will be: <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-f21ydwhfpdjz7xjs.jpg" /> (A) 2A (B) 5A (C) 3A (D) 4A

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-f21ydwhfpdjzwjt7.jpg" /> i=i2+i2 (V - 0/2)=(20 - V/2)+(10 - V/4) 2V+V-10+2(.V-20.)=0 5V-50=0 V=10V i=(10/2)=5A

Q. When the switch $S,$ in the circuit shown, is closed, then the value of current $i$ will be:

$2 A$

$5 A$

$3 A$

$4 A$

$i = i_{2} + i_{2}$
$\frac{V - 0}{2} = \frac{20 - V}{2} + \frac{10 - V}{4}$
$2 V + V - 10 + 2 (V - 20) = 0$
$5 V - 50 = 0$
$V = 10 V$
$i = \frac{10}{2} = 5 A$

Q. When the switch S, in the circuit shown, is closed, then the value of current i will be:

2A

5A

3A

4A