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Q. When the switch $S,$ in the circuit shown, is closed, then the value of current $i$ will be:
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$i=i_{2}+i_{2}$
$\frac{V - 0}{2}=\frac{20 - V}{2}+\frac{10 - V}{4}$
$2V+V-10+2\left(\right.V-20\left.\right)=0$
$5V-50=0$
$V=10V$
$i=\frac{10}{2}=5A$