Question

When the switch $S$, in the circuit shown, is closed, then the value of current $i$ will be :

• A. 3 A
• B. 5 A
• C. 4 A
• D. 2 A

Answer 1

Answer: (B)

Let voltage at $C=xv$
KCL : $i_1+i_2=i$
$\frac{20-x}{2}+\frac{10-x}{4}=\frac{x-0}{2}$
$\Rightarrow x=10$
and $i=5amp$.