When the switch is closed, then the initial current through 1 Ω resistor is (see figure)

Question

When the switch is closed, then the initial current through 1 Ω resistor is (see figure) (A) 12 A (B) 4 A (C) (10/7) A (D) 3 A

Tardigrade Admin · Accepted Answer

At t=0, the capacitor behaves as a short circuit. The corresponding circuit is shown in figure. According to the loop rule, <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/58746a371b6ff048b8f0786ea8d01907-.png" /> 12-3 I=0 or I=4 A

Q. When the switch is closed, then the initial current through $1 Ω$ resistor is (see figure)

$12 A$

$4 A$

$\frac{10}{7} A$

$3 A$

At $t = 0$ , the capacitor behaves as a short circuit. The corresponding circuit is shown in figure. According to the loop rule,

$12 - 3 I = 0$ or $I = 4 A$

Q. When the switch is closed, then the initial current through 1Ω resistor is (see figure)

12A

4A

710​A

3A