When the same quantity of heat is absorbed by a system at two different temperatures T1 and T2, such that T1 T2, change in entropies are Δ S1 and Δ S2 respectively. Then

Question

When the same quantity of heat is absorbed by a system at two different temperatures T1 and T2, such that T1 > T2, change in entropies are Δ S1 and Δ S2 respectively. Then (A) Δ S1 < Δ S2 (B) Δ S1 = Δ S2 (C) S1 > S2 (D) Δ S2 < Δ S1

Tardigrade Admin · Accepted Answer

In thermodynamics, we are concerned about entropy change due to the transfer of heat.

Which we can write in the form,

Δ S = q / T

, here

q

is constant.

So,

Δ S \propto 1/ T

We are given,

T_{1} > T_{2}

, so the actual relation between the entropies will be

Δ S_{1} < Δ S_{2}

Q. When the same quantity of heat is absorbed by a system at two different temperatures $T_{1}$ and $T_{2}$ , such that $T_{1} > T_{2}$ , change in entropies are $Δ S_{1}$ and $Δ S_{2}$ respectively. Then

$Δ S_{1} < Δ S_{2}$

$Δ S_{1} = Δ S_{2}$

$S_{1} > S_{2}$

$Δ S_{2} < Δ S_{1}$

In thermodynamics, we are concerned about entropy change due to the transfer of heat.

Which we can write in the form, $Δ S = q / T$ , here $q$ is constant.

So, $Δ S \propto 1/ T$

We are given, $T_{1} > T_{2}$ , so the actual relation between the entropies will be $Δ S_{1} < Δ S_{2}$

Q. When the same quantity of heat is absorbed by a system at two different temperatures T1​ and T2​, such that T1​>T2​, change in entropies are ΔS1​ and ΔS2​ respectively. Then

ΔS1​<ΔS2​

ΔS1​=ΔS2​

S1​>S2​

ΔS2​<ΔS1​