When the imidazole ring of Histidine is protonated, tendency of nitrogen to be protonated (proton migrates from - COOH) is in the order

Question

When the imidazole ring of Histidine is protonated, tendency of nitrogen to be protonated (proton migrates from - COOH) is in the order (A) β > &gamma; > α (B)  &gamma; > β > α (C)  &gamma; > α > β (D)  β > α > &gamma;

Tardigrade Admin · Accepted Answer

&gamma; (NH2) In close to COOH, in β(-NH2), the lone pair of electrons Is involved in resonance, nod flie lone pair on α(- N=) is intact on N- atom.

Q. When the imidazole ring of Histidine is protonated, tendency of nitrogen to be protonated (proton migrates from $- COO H$ ) is in the order

$β > γ > α$

$γ > β > α$

$γ > α > β$

$β > α > γ$

$γ (N H_{2})$ In close to $COO H$ , in $β (- N H_{2})$ , the lone pair of electrons Is involved in resonance, nod flie lone pair on $α (- N =)$ is intact on $N$ - atom.

Q. When the imidazole ring of Histidine is protonated, tendency of nitrogen to be protonated (proton migrates from −COOH) is in the order

β>γ>α

γ>β>α

γ>α>β

β>α>γ