When the complete Young's double slit experiment is immersed in water, the fringes

Question

When the complete Young's double slit experiment is immersed in water, the fringes (A) remain unaltered (B) become wider (C) become narrower (D) disappear

Tardigrade Admin · Accepted Answer

When Youngâs double slit experiment is repeated in water, instead of air. λ'=(λ/u), i.e., wavelength decreases . β=(λ' D/d), i.e., fringe width decreases ∴ The fringes become narrower

Q. When the complete Young's double slit experiment is immersed in water, the fringes

remain unaltered

become wider

become narrower

disappear

When Young’s double slit experiment is repeated in water, instead of air.
$λ^{'} = \frac{λ}{u}$ , i.e.,
wavelength decreases . $β = \frac{λ ^{'} D}{d}$ , i.e., fringe width decreases
$∴$ The fringes become narrower

Q. When the complete Young's double slit experiment is immersed in water, the fringes

remain unaltered

become wider

become narrower

disappear

When Young’s double slit experiment is repeated in water, instead of air. λ′=uλ​, i.e., wavelength decreases . β=dλ′D​, i.e., fringe width decreases ∴ The fringes become narrower

When Young’s double slit experiment is repeated in water, instead of air.
$λ^{'} = \frac{λ}{u}$ , i.e.,
wavelength decreases . $β = \frac{λ ^{'} D}{d}$ , i.e., fringe width decreases
$∴$ The fringes become narrower