Question

When sodium nitrate is heated above $600^{\circ }$ then:

• A. only $N{a}_{2}O$ is formed
• B. only $N_2$ is formed
• C. only $O_2$ is formed
• D. all are formed

Answer 1

Answer: (D)

On heating $NaN{O}_3$ above $600^{\circ }CN{a}_{2}O,O_2$ and $N_2$ all is obtained as:
$4NaN{O}_3\stackrel{800^{\circ }C}{\to }2N{a}_{2}O+5O_2+2N_2$