When SO2 is passed through acidified K2Cr2O7 solution

Question

When SO2 is passed through acidified K2Cr2O7 solution (A) the solution turns blue (B) the solution is decolourised (C) SO2 is reduced (D) green Cr2(SO4)3 is formed

Tardigrade Admin · Accepted Answer

K2Cr2O7 + 4H2SO4 arrow K2SO4 + underset textGreenCr2(SO4)3+ 4H2O + 3O SO2 + O + H2O arrow H2SO4

Q. When $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution

the solution turns blue

the solution is decolourised

$S O_{2}$ is reduced

green $C r_{2} (S O_{4})_{3}$ is formed

$K_{2} C r_{2} O_{7} + 4 H_{2} S O_{4} \to K_{2} S O_{4} + Green C r_{2} (S O_{4})_{3} + 4 H_{2} O + 3 O$
$S O_{2} + O + H_{2} O \to H_{2} S O_{4}$

Q. When SO2​ is passed through acidified K2​Cr2​O7​ solution

the solution turns blue

the solution is decolourised

SO2​ is reduced

green Cr2​(SO4​)3​ is formed

K2​Cr2​O7​+4H2​SO4​→K2​SO4​+GreenCr2​(SO4​)3​​+4H2​O+3O SO2​+O+H2​O→H2​SO4​

Q. When $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution

$S O_{2}$ is reduced

green $C r_{2} (S O_{4})_{3}$ is formed

$K_{2} C r_{2} O_{7} + 4 H_{2} S O_{4} \to K_{2} S O_{4} + Green C r_{2} (S O_{4})_{3} + 4 H_{2} O + 3 O$
$S O_{2} + O + H_{2} O \to H_{2} S O_{4}$