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Chemistry
When SO2 is passed through acidified K2Cr2O7 solution
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Q. When $SO_2$ is passed through acidified $K_2Cr_2O_7$ solution
The p-Block Elements - Part2
A
the solution turns blue
0%
B
the solution is decolourised
50%
C
$SO_2$ is reduced
0%
D
green $Cr_2(SO_4)_3$ is formed
50%
Solution:
$K_2Cr_2O_7 + 4H_2SO_4 \rightarrow K_2SO_4 +\underset{\text{Green}}{Cr_2(SO_4)_3}+ 4H_2O + 3O$
$SO_2 + O + H_2O \rightarrow H_2SO_4$