When reacts with KOH in the presence of water (through SN2 reaction mechanism), then the stereochemistry of product so formed will be -

Question

When <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-vobasiixfzsd2dhn.jpg" /> reacts with KOH in the presence of water (through SN​2 reaction mechanism), then the stereochemistry of product so formed will be - (A) R (B) S (C) Mixture of R and S (D) Partial S + racemic mixture

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-vobasiixfzsdz6xz.jpg" /> In SN2 inversion takes place. That means here reactant is in configuration R then product of this reaction will be of configuration S.

Q. When reacts with KOH in the presence of water (through S_N2 reaction mechanism), then the stereochemistry of product so formed will be -

R

S

Mixture of R and S

Partial S + racemic mixture

In S_N2 inversion takes place. That means here reactant is in configuration R then product of this reaction will be of configuration S.

Q. When reacts with KOH in the presence of water (through SN​2 reaction mechanism), then the stereochemistry of product so formed will be -

R

S

Mixture of R and S

Partial S + racemic mixture

In SN2 inversion takes place. That means here reactant is in configuration R then product of this reaction will be of configuration S.

Q. When reacts with KOH in the presence of water (through S_N2 reaction mechanism), then the stereochemistry of product so formed will be -

In S_N2 inversion takes place. That means here reactant is in configuration R then product of this reaction will be of configuration S.