When r, P and M represent rate of diffusion, pressure and molecular mass, respectively, then the ratio of the rates of diffusion (rA/rB) of two gases A and B, is given as:

Question

When r, P and M represent rate of diffusion, pressure and molecular mass, respectively, then the ratio of the rates of diffusion (rA/rB) of two gases A and B, is given as: (A) (PA/PB) (MB/MA)1/2 (B) (PA/PB)1/2 (MB/MA) (C) (PA/PB) (MA/MB)1/2 (D) (PA/PB)1/2 (MA/MB)

Tardigrade Admin · Accepted Answer

r propto (P/√M) (rA/rB)= (PA/PB) √(MB/MA)

Q. When r, P and M represent rate of diffusion, pressure and molecular mass, respectively, then the ratio of the rates of diffusion $(r_{A} / r_{B})$ of two gases A and B, is given as:

$(P_{A} / P_{B}) (M_{B} / M_{A})^{1/2}$

$(P_{A} / P_{B})^{1/2} (M_{B} / M_{A})$

$(P_{A} / P_{B}) (M_{A} / M_{B})^{1/2}$

$(P_{A} / P_{B})^{1/2} (M_{A} / M_{B})$

$r \propto \frac{P}{M}$
$\frac{r _{A}}{r _{B}} = \frac{P _{A}}{P _{B}} \frac{M _{B}}{M _{A}}$

Q. When r, P and M represent rate of diffusion, pressure and molecular mass, respectively, then the ratio of the rates of diffusion (rA​/rB​) of two gases A and B, is given as:

(PA​/PB​)(MB​/MA​)1/2

(PA​/PB​)1/2(MB​/MA​)

(PA​/PB​)(MA​/MB​)1/2

(PA​/PB​)1/2(MA​/MB​)