When photons of energy h v fall on an aluminium plate (of work function E0 ), photoelectrons of maximum kinetic energy K are ejected. If the frequency of radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be

Question

When photons of energy h v fall on an aluminium plate (of work function E0 ), photoelectrons of maximum kinetic energy K are ejected. If the frequency of radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be (A)  K + E0  (B) 2 K (C) K (D)  k+h upsilon

Tardigrade Admin · Accepted Answer

According to given situation hv = E 0+ K 2 hv = E 0+ K ' ⇒ K'= K + hv

Q. When photons of energy $h v$ fall on an aluminium plate (of work function $E_{0}$ ), photoelectrons of maximum kinetic energy $K$ are ejected. If the frequency of radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be

$K + E_{0}$

$2 K$

$K$

$k + h υ$

According to given situation
$h v = E_{0} + K$ & $2 h v = E_{0} + K^{'}$
$\Rightarrow K^{'} = K + h v$

Q. When photons of energy hv fall on an aluminium plate (of work function E0​ ), photoelectrons of maximum kinetic energy K are ejected. If the frequency of radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be

K+E0​

2K

K

k+hυ

According to given situation hv=E0​+K & 2hv=E0​+K′ ⇒K′=K+hv

Q. When photons of energy $h v$ fall on an aluminium plate (of work function $E_{0}$ ), photoelectrons of maximum kinetic energy $K$ are ejected. If the frequency of radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be

$K + E_{0}$

$2 K$

$K$

$k + h υ$

According to given situation
$h v = E_{0} + K$ & $2 h v = E_{0} + K^{'}$
$\Rightarrow K^{'} = K + h v$