When NH 3 accepts a proton in aqueous solution

Question

When NH 3 accepts a proton in aqueous solution (A) H - N - H bond angle changes from 107° to 109.5° (B)  % s -character of the hybrid orbital of N in both NH 3 and the product remains the same (C) both (a) and (b) (D) none of the above

Tardigrade Admin · Accepted Answer

NH 3 is in s p3 hybridised state with one lone pair. Due to the repulsion of lone pair-bond pair, the bond angle of ammonia is lower than 109° 28 prime.

When this lone pair is donated to H +, the lone pair-bond pair repulsion diminishes and bond angle increase to 109.5° without affecting hybridisation or s -character.

Q. When $N H_{3}$ accepts a proton in aqueous solution

$H - N - H$ bond angle changes from $10 7^{\circ}$ to $109. 5^{\circ}$

$% s$ -character of the hybrid orbital of $N$ in both $N H_{3}$ and the product remains the same

both (a) and (b)

none of the above

Q. When NH3​ accepts a proton in aqueous solution

H−N−H bond angle changes from 107∘ to 109.5∘

%s -character of the hybrid orbital of N in both NH3​ and the product remains the same

both (a) and (b)

none of the above

Q. When $N H_{3}$ accepts a proton in aqueous solution

$H - N - H$ bond angle changes from $10 7^{\circ}$ to $109. 5^{\circ}$

$% s$ -character of the hybrid orbital of $N$ in both $N H_{3}$ and the product remains the same