When neo-pentyl alcohol is treated with H 2 SO 4, a mixture of two alkenes (85: 15) is formed. Which statements is correct about these alkenes?

Question

When neo-pentyl alcohol is treated with H 2 SO 4, a mixture of two alkenes (85: 15) is formed. Which statements is correct about these alkenes? (A) Both give same major product with HBr. (B) Both give same products (major) with HBr / R2 O 2 / light. (C) The alkene which is formed in 85 % concentration has higher heat of hydrogenation than the other one obtained in 15 % concentration. (D) Both give same product on ozonolysis.

Tardigrade Admin · Accepted Answer

Q. When neo-pentyl alcohol is treated with $H_{2} S O_{4}$ , a mixture of two alkenes $(85 : 15)$ is formed. Which statements is correct about these alkenes?

Both give same major product with $H B r$ .

Both give same products (major) with $H B r / R_{2} O_{2} /$ light.

The alkene which is formed in $85%$ concentration has higher heat of hydrogenation than the other one obtained in $15%$ concentration.

Both give same product on ozonolysis.

Q. When neo-pentyl alcohol is treated with H2​SO4​, a mixture of two alkenes (85:15) is formed. Which statements is correct about these alkenes?

Both give same major product with HBr.

Both give same products (major) with HBr/R2​O2​/ light.

The alkene which is formed in 85% concentration has higher heat of hydrogenation than the other one obtained in 15% concentration.

Both give same product on ozonolysis.

Q. When neo-pentyl alcohol is treated with $H_{2} S O_{4}$ , a mixture of two alkenes $(85 : 15)$ is formed. Which statements is correct about these alkenes?

Both give same major product with $H B r$ .

Both give same products (major) with $H B r / R_{2} O_{2} /$ light.

The alkene which is formed in $85%$ concentration has higher heat of hydrogenation than the other one obtained in $15%$ concentration.