When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is

Question

When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is (A) Fe (B) Zn (C) Ca (D) Al

Tardigrade Admin · Accepted Answer

2Al+6H2O arrow 2Al(O H)3 downarrow+3H2 Al(OH)3+NaOH arrow Na[(OH)4](soluble)

Q. When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is

Fe

Zn

Ca

Al

$2 A l + 6 H_{2} O \to 2 A l (O H)_{3} ↓ + 3 H_{2}$

$A l (O H)_{3} + N a O H \to N a [(O H)_{4}] (so l u b l e)$

Q. When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is

Fe

Zn

Ca

Al

2Al+6H2​O→2Al(OH)3​↓+3H2​ Al(OH)3​+NaOH→Na[(OH)4​](soluble)

$2 A l + 6 H_{2} O \to 2 A l (O H)_{3} ↓ + 3 H_{2}$

$A l (O H)_{3} + N a O H \to N a [(O H)_{4}] (so l u b l e)$