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Q. When metal 'M' is treated with NaOH, a white gelatinous precipitate 'X' is obtained, which is soluble in excess of NaOH. Compound 'X' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal 'M' is

NTA AbhyasNTA Abhyas 2020The p-Block Elements - Part2

Solution:

$2Al+6H_{2}O \rightarrow 2Al\left(O H\right)_{3}\downarrow+3H_{2}$

$Al\left(OH\right)_{3}+NaOH \rightarrow Na\left[\left(OH\right)_{4}\right]\left(soluble\right)$