When mercuric iodide is added to the aqueous solution of potassium iodide

Question

When mercuric iodide is added to the aqueous solution of potassium iodide (A) freezing point is raised (B) freezing point is lowered (C) freezing point does not change (D) boiling point does not change

Tardigrade Admin · Accepted Answer

Addition of HgI2 to KI solution establishes the following equilibrium: HgI2 +2KI leftharpoons K2[HgI4] The above equilibrium decreases the number of ions (4 ions on left side of reactions becomes three ions on right side), hence rises the freezing point.

Q. When mercuric iodide is added to the aqueous solution of potassium iodide

freezing point is raised

freezing point is lowered

freezing point does not change

boiling point does not change

Addition of $H g I_{2}$ to $K I$ solution establishes the following equilibrium:
$H g I_{2} + 2 K I ⇌ K_{2} [H g I_{4}]$
The above equilibrium decreases the number of ions ( $4$ ions on left side of reactions becomes three ions on right side), hence rises the freezing point.

Q. When mercuric iodide is added to the aqueous solution of potassium iodide

freezing point is raised

freezing point is lowered

freezing point does not change

boiling point does not change

Addition of HgI2​ to KI solution establishes the following equilibrium: HgI2​+2KI⇌K2​[HgI4​] The above equilibrium decreases the number of ions (4 ions on left side of reactions becomes three ions on right side), hence rises the freezing point.

Addition of $H g I_{2}$ to $K I$ solution establishes the following equilibrium:
$H g I_{2} + 2 K I ⇌ K_{2} [H g I_{4}]$
The above equilibrium decreases the number of ions ( $4$ ions on left side of reactions becomes three ions on right side), hence rises the freezing point.