Question

When $KMn{O}_4$ reacts with $KBr$ in alkaline medium gives bromate ion. Then oxidation state of $Mn$ changes from $+7$ to

• A. +6
• B. +4
• C. +3
• D. +2

Answer 1

Answer: (B)

$2\stackrel{+7}{M}n{O}_4^{-}+B{r}^{-}+H_{2}O\to 2\stackrel{+4}{M}n{O}_2+Br{O}_3^{-}+2O{H}^{-}$