Question

When $I^{-}$ is oxidised by $KMn{O}_4$ in alkaline medium, $I^{-}$ converts into

• A. $I{O}_3^{-}$
• B. $I_2$
• C. $I{O}_4^{-}$
• D. $I{O}^{-}$

Answer 1

Answer: (A)

$I^{-}$ is oxidised by $Mn{O}_4$ in alkaline medium to form $I{O}_3^{-}$
$2KMn{O}_4+KI+H_{2}O⟶2KOH+2Mn{O}_2+KI{O}_3$