When hydrochloric acid is added to cobalt nitrate solution at room temperature, the following reaction takes place and the reaction mixture becomes blue. On cooling the mixture, it becomes pink. On the basis of this information mark the correct answer. underset textPink[Co(H2O)6]3+(aq) + 4Cl-(aq) leftharpoons underset textBlue[CoCl4]2-(aq) + 6H2O(l)

Question

When hydrochloric acid is added to cobalt nitrate solution at room temperature, the following reaction takes place and the reaction mixture becomes blue. On cooling the mixture, it becomes pink. On the basis of this information mark the correct answer. underset textPink[Co(H2O)6]3+(aq) + 4Cl-(aq) leftharpoons underset textBlue[CoCl4]2-(aq) + 6H2O(l) (A) Δ H > 0 for the reaction (B) Δ H < 0 for the reaction (C) Δ H = 0 for the reaction (D) The sign of Δ H cannot be predicted on the basis of this information

Tardigrade Admin · Accepted Answer

underset textPink[Co(H2O)6]3+(aq)+ 4Cl-(aq) leftharpoons underset textBlue[CoCl4]2-(aq) + 6H2O(l) On cooling the mixture, the reaction proceeds in backward direction and on heating the mixture, the reaction proceeds in forward direction, hence, the reaction is endothermic i.e., Δ H > 0

$Δ H > 0$ for the reaction

$Δ H < 0$ for the reaction

$Δ H = 0$ for the reaction

The sign of $Δ H$ cannot be predicted on the basis of this information

ΔH>0 for the reaction

ΔH<0 for the reaction

ΔH=0 for the reaction

The sign of ΔH cannot be predicted on the basis of this information

Pink[Co(H2​O)6​](aq)3+​​+4Cl(aq)−​⇌Blue[CoCl4​](aq)2−​​+6H2​O(l)​ On cooling the mixture, the reaction proceeds in backward direction and on heating the mixture, the reaction proceeds in forward direction, hence, the reaction is endothermic i.e., ΔH>0

$Δ H > 0$ for the reaction

$Δ H < 0$ for the reaction

$Δ H = 0$ for the reaction

The sign of $Δ H$ cannot be predicted on the basis of this information