When heat is given to a gas in an isothermal change, the result will be

Question

When heat is given to a gas in an isothermal change, the result will be (A) external work done (B) rise in temperature (C) increase in internal energy (D) external work done and also rise in temperature

Tardigrade Admin · Accepted Answer

For an isothermal change, Δ T=0 ⇒ Δ U=n Cν Δ T=0 Q=Δ U+W, but Δ U=0 So, W=Q As Q is positive here, W will be positive too, i.e. external work is done by the system.

Q. When heat is given to a gas in an isothermal change, the result will be

external work done

rise in temperature

increase in internal energy

external work done and also rise in temperature

For an isothermal change, $Δ T = 0$
$\Rightarrow Δ U = n C_{ν} Δ T = 0$
$Q = Δ U + W,$ but $Δ U = 0$
So, $W = Q$
As $Q$ is positive here, $W$ will be positive too, i.e. external work is done by the system.

Q. When heat is given to a gas in an isothermal change, the result will be

external work done

rise in temperature

increase in internal energy

external work done and also rise in temperature

For an isothermal change, ΔT=0 ⇒ΔU=nCν​ΔT=0 Q=ΔU+W, but ΔU=0 So, W=Q As Q is positive here, W will be positive too, i.e. external work is done by the system.

For an isothermal change, $Δ T = 0$
$\Rightarrow Δ U = n C_{ν} Δ T = 0$
$Q = Δ U + W,$ but $Δ U = 0$
So, $W = Q$
As $Q$ is positive here, $W$ will be positive too, i.e. external work is done by the system.