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Q.
When heat is given to a gas in an isothermal change, the result will be
Thermodynamics
Solution:
For an isothermal change, $\Delta T=0$
$\Rightarrow \Delta U=n C_{\nu} \Delta T=0$
$Q=\Delta U+W,$ but $\Delta U=0$
So, $W=Q$
As $Q$ is positive here, $W$ will be positive too, i.e. external work is done by the system.