When H2O2 is shaken with an acidified solution of K2 Cr2O7 in presence of ether, the ethereal layer turns blue due to the formation of

Question

When H2O2 is shaken with an acidified solution of K2 Cr2O7 in presence of ether, the ethereal layer turns blue due to the formation of (A) Cr2O3 (B) CrO2-4 (C) Cr2 (SO4)3 (D) CrO5

Tardigrade Admin · Accepted Answer

K 2 Cr 2 O 7+ H 2 SO 4+ 4 H 2 O 2 arrow K 2 SO 4+5 H 2 O + underset textdark blue2 CrO 5

Q. When $H_{2} O_{2}$ is shaken with an acidified solution of $K_{2} C r_{2} O_{7}$ in presence of ether, the ethereal layer turns blue due to the formation of

$C r_{2} O_{3}$

$C r O_{4}^{2 -}$

$C r_{2} (S O_{4})_{3}$

$C r O_{_{5}}$

$K_{2} C r_{2} O_{7} + H_{2} S O_{4} + 4 H_{2} O_{2} \to$
$K_{2} S O_{4} + 5 H_{2} O + dark blue 2 C r O_{5}$

Q. When H2​O2​ is shaken with an acidified solution of K2​Cr2​O7​ in presence of ether, the ethereal layer turns blue due to the formation of

Cr2​O3​

CrO42−​

Cr2​(SO4​)3​

CrO5​​