When excess of silver nitrate solution is added to a beaker containing 200 mL of 0.01 M pentaaquachloridochromium (III) chloride solution, the mass of silver chloride obtained (in mg ) is. [Atomic mass: Chlorine =35.5 u, silver =108 u ].

Question

When excess of silver nitrate solution is added to a beaker containing 200 mL of 0.01 M pentaaquachloridochromium (III) chloride solution, the mass of silver chloride obtained (in mg ) is. [Atomic mass: Chlorine =35.5 u, silver =108 u ]. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

200 mL of 0.01 M solution of the complex contains 0.01 × 0.200=0.002 mol of complex The chemical formula of pentaaquachloridochromium(III) chloride is [ Cr ( H 2 O )5 Cl ] Cl 2. On ionization, one mole of the complex gives two Cl -ions in solution. ∴ The given solution contains 2 × 0.002 mol of Cl - ions =0.004 mol of Cl - ions AgNO 3+ Cl - longrightarrow AgCl downarrow+ NO 3 - 1 mol Cl - ions ≡ 1 mol AgCl ∴ 0.004 mol Cl -ions ≡ 0.004 mol AgCl =0.004 × 143.5 =0.574 g AgCl =574 mg AgCl

Q. When excess of silver nitrate solution is added to a beaker containing 200mL of 0.01M pentaaquachloridochromium (III) chloride solution, the mass of silver chloride obtained (in mg ) is_____. [Atomic mass: Chlorine =35.5u, silver =108u].

Q. When excess of silver nitrate solution is added to a beaker containing $200 m L$ of $0.01 M$ pentaaquachloridochromium (III) chloride solution, the mass of silver chloride obtained (in $m g$ ) is_____.
[Atomic mass: Chlorine $= 35.5 u$ , silver $= 108 u]$ .