When ethyl nitrile is subjected to reduction with Sn/HCl, the pair of compounds formed are

Question

When ethyl nitrile is subjected to reduction with Sn/HCl, the pair of compounds formed are (A) Ethanol, hydroxylamine (B) Ethanol, hydrochloride, ammonium hydroxide (C) Ethanal, NH2OH (D) C2H5OH, H2O

Tardigrade Admin · Accepted Answer

C2H5 — O — N=O xrightarrow[[H]]Sn/Hcl C2H5OH+NH2OH+HCl

Q. When ethyl nitrile is subjected to reduction with Sn/HCl, the pair of compounds formed are

Ethanol, hydroxylamine

Ethanol, hydrochloride, ammonium hydroxide

Ethanal, $N H_{2} O H$

$C_{2} H_{5} O H, H_{2} O$

$C_{2} H_{5} — O — N = O S n / Hc l [H] C_{2} H_{5} O H + N H_{2} O H + H Cl$

Q. When ethyl nitrile is subjected to reduction with Sn/HCl, the pair of compounds formed are

Ethanol, hydroxylamine

Ethanol, hydrochloride, ammonium hydroxide

Ethanal, NH2​OH

C2​H5​OH,H2​O

C2​H5​—O—N=OSn/Hcl[H]​C2​H5​OH+NH2​OH+HCl

Ethanal, $N H_{2} O H$

$C_{2} H_{5} O H, H_{2} O$

$C_{2} H_{5} — O — N = O S n / Hc l [H] C_{2} H_{5} O H + N H_{2} O H + H Cl$