When equal volumes of the following solutions are mixed precipitation of AgCl (Ksp = 1.8 x × 10 - 1 0 ) will occur only with

Question

When equal volumes of the following solutions are mixed precipitation of AgCl (Ksp = 1.8 x × 10 - 1 0 ) will occur only with (A)  10 - 4 M ( Ag+ ) and 10 - 4 M ( Cl- ) (B)  10 - 5 M ( Ag+ ) and 10 - 5 M ( Cl- ) (C)  10 - 6 M ( Ag+ ) and 10 - 6 M ( Cl- ) (D)  10 - 10 M ( Ag+ ) and 10 - 10 M ( Cl- )

Tardigrade Admin · Accepted Answer

For precipitation to occur, K s p < Q sp , Q sp = ( ( 10 - 4 / 2 ) ) ( ( 10 - 4 / 2 ) ) = 2.5 × 10 - 9 > K sp Hence, precipitate will be formed in this case. In all other case, Qsp < Ksp and no precipitation will occur.

Q. When equal volumes of the following solutions are mixed precipitation of $A g Cl (K_{s p} = 1.8 x \times 1 0^{- 10})$ will occur only with

$1 0^{- 4} M (A g^{+})$ and $1 0^{- 4} M (C l^{-})$

$1 0^{- 5} M (A g^{+})$ and $1 0^{- 5} M (C l^{-})$

$1 0^{- 6} M (A g^{+})$ and $1 0^{- 6} M (C l^{-})$

$1 0^{- 10} M (A g^{+})$ and $1 0^{- 10} M (C l^{-})$

For precipitation to occur, $K_{s p} < Q_{s p}$ ,
$Q_{s p} = (\frac{1 0 ^{- 4}}{2}) (\frac{1 0 ^{- 4}}{2}) = 2.5 \times 1 0^{- 9} > K_{s p}$
Hence, precipitate will be formed in this case.
In all other case, $Q_{s p} < K_{s p}$ and no precipitation will occur.

Q. When equal volumes of the following solutions are mixed precipitation of AgCl(Ksp​=1.8x×10−10) will occur only with

10−4M(Ag+) and 10−4M(Cl−)

10−5M(Ag+) and 10−5M(Cl−)

10−6M(Ag+) and 10−6M(Cl−)

10−10M(Ag+) and 10−10M(Cl−)