Tardigrade
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Tardigrade
Question
Chemistry
When enthalpy and entropy change for a chemical reaction are -2.5 × 103 cal and 7.4 cal deg -1 respectively. Predict that reaction at 298 K is
Q. When enthalpy and entropy change for a chemical reaction are
−
2.5
×
1
0
3
cal and
7.4
c
a
l
d
e
g
−
1
respectively. Predict that reaction at
298
K
is
2805
204
Thermodynamics
Report Error
A
spontaneous
63%
B
reversible
17%
C
irreversible
7%
D
non-spontaneous
13%
Solution:
Δ
G
=
Δ
H
−
T
Δ
S
Given
Δ
H
=
−
ve and
Δ
S
=
+
ve. So
Δ
G
must be negative, hence reaction will be spontaneous.