When current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self - inductance of the coil is :

Question

When current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self - inductance of the coil is : (A) 0.67 H (B) 1.67 H (C) 3 H (D) 6 H

Tardigrade Admin · Accepted Answer

According to Faradayâs law of electromagnetic induction, Induced emf, e =(Ldi/dt) 50 = L((5-2/0.1 sec)) ⇒ L = (50×0.1/3) = (5/3) = 1.67 H

Q. When current in a coil changes from $5 A$ to $2 A$ in $0.1 s$ , an average voltage of $50 V$ is produced. The self - inductance of the coil is :

0.67 H

1.67 H

3 H

6 H

According to Faraday’s law of electromagnetic induction,
Induced emf, $e = \frac{L d i}{d t}$
$50 = L (\frac{5 - 2}{0.1 sec})$
$\Rightarrow L = \frac{50 \times 0.1}{3} = \frac{5}{3} = 1.67 H$

Q. When current in a coil changes from 5A to 2A in 0.1s, an average voltage of 50V is produced. The self - inductance of the coil is :

0.67 H

1.67 H

3 H

6 H

According to Faraday’s law of electromagnetic induction, Induced emf, e=dtLdi​ 50=L(0.1sec5−2​) ⇒L=350×0.1​=35​=1.67H

Q. When current in a coil changes from $5 A$ to $2 A$ in $0.1 s$ , an average voltage of $50 V$ is produced. The self - inductance of the coil is :

According to Faraday’s law of electromagnetic induction,
Induced emf, $e = \frac{L d i}{d t}$
$50 = L (\frac{5 - 2}{0.1 sec})$
$\Rightarrow L = \frac{50 \times 0.1}{3} = \frac{5}{3} = 1.67 H$