When Cl2 is passed through hot NaOH, oxidation number of Cl changes from

Question

When Cl2 is passed through hot NaOH, oxidation number of Cl changes from (A) -1 to 0 (B) 0 to -1 (C) 0 to +7 (D) 0 to +5

Tardigrade Admin · Accepted Answer

The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is

3 C l_{2} + 6 N a O H ⟶ N a Cl O_{3} + 5 N a Cl + 3 H_{2} O

Oxidation number of

Cl

is 0 in

C l_{2}, - 1

in

N a Cl

and

+ 5 in N a Cl O_{3}

So the oxidation number of chlorine changes from Zero to

- 1

and Zero to

+ 5

.

Q. When Cl2​ is passed through hot NaOH, oxidation number of Cl changes from