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  4. When Cl2 is passed through hot NaOH, oxidation number of Cl changes from

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Q. When $Cl_2$ is passed through hot $NaOH$, oxidation number of $Cl$ changes from

Redox Reactions

Solution:

The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is
$3 Cl _{2}+6 NaOH \longrightarrow NaClO _{3}+5 NaCl +3 H _{2} O$
Oxidation number of $Cl$ is 0 in $Cl _{2},-1$ in $NaCl$ and $+5 in NaClO _{3}$
So the oxidation number of chlorine changes from Zero to $-1$ and Zero to $+5$.