When CH3COOCH3 + HCl is titrated with NaOH then at neutral point the colour of phenolphthalein becomes colourless from pink due to

Question

When CH3COOCH3 + HCl is titrated with NaOH then at neutral point the colour of phenolphthalein becomes colourless from pink due to (A) formation of CH3OH (B) formation of CH3COOH which acts as a weak acid (C) phenolphthalein vaporizes (D) presence of HCl

Tardigrade Admin · Accepted Answer

NaOH solution is taken in a conical flask with phenolphthalein indicator (pink colour) and CH3COOCH3 + HCl solution is added from burette slowly. First, HCl left after hydrolysis of ester (being a strong acid) gets consumed then CH3COOH being a weak acid will bring the titration to the neutralisation point. CH3COOCH3 xrightarrow[H+] H2O CH3COOH + CH3OH HCl + NaOH arrow NaCl + H2O CH3COOH + NaOH arrow CH3COONa

Q. When $C H_{3} COOC H_{3} + H Cl$ is titrated with $N a O H$ then at neutral point the colour of phenolphthalein becomes colourless from pink due to

formation of $C H_{3} O H$

formation of $C H_{3} COO H$ which acts as a weak acid

phenolphthalein vaporizes

presence of $H Cl$

Q. When CH3​COOCH3​+HCl is titrated with NaOH then at neutral point the colour of phenolphthalein becomes colourless from pink due to

formation of CH3​OH

formation of CH3​COOH which acts as a weak acid

phenolphthalein vaporizes

presence of HCl

Q. When $C H_{3} COOC H_{3} + H Cl$ is titrated with $N a O H$ then at neutral point the colour of phenolphthalein becomes colourless from pink due to

formation of $C H_{3} O H$

formation of $C H_{3} COO H$ which acts as a weak acid

presence of $H Cl$