When calomel reacts with NH4OH, we get

Question

When calomel reacts with NH4OH, we get (A) Hg2O (B) HgO (C) HgNH2Cl (D) NH2-Hg-Hg-Cl

Tardigrade Admin · Accepted Answer

When calomel reacts with NH 4 OH, it turns black due to the formation of a mixture of mercury and ammonium basic mercury (II) chloride. underset text(calomel)Hg 2 Cl 2+2 NH 4 OH arrow NH 4 Cl +2 H 2 O + Hg + HgNH 2 Cl

Q. When calomel reacts with NH₄OH, we get

Hg₂O

HgO

HgNH₂Cl

NH₂-Hg-Hg-Cl

When calomel reacts with $N H_{4} O H$ , it turns black due to the formation of a mixture of mercury and ammonium basic mercury (II) chloride.
$(calomel) H g_{2} C l_{2} + 2 N H_{4} O H \to N H_{4} Cl + 2 H_{2} O + H g + H g N H_{2} Cl$

Q. When calomel reacts with NH4OH, we get

Hg2O

HgO

HgNH2Cl

NH2-Hg-Hg-Cl

When calomel reacts with NH4​OH, it turns black due to the formation of a mixture of mercury and ammonium basic mercury (II) chloride. (calomel)Hg2​Cl2​​+2NH4​OH→NH4​Cl+2H2​O+Hg+HgNH2​Cl

Q. When calomel reacts with NH₄OH, we get

Hg₂O

HgNH₂Cl

NH₂-Hg-Hg-Cl

When calomel reacts with $N H_{4} O H$ , it turns black due to the formation of a mixture of mercury and ammonium basic mercury (II) chloride.
$(calomel) H g_{2} C l_{2} + 2 N H_{4} O H \to N H_{4} Cl + 2 H_{2} O + H g + H g N H_{2} Cl$