When aniline is treated with bromine-water, it forms

Question

When aniline is treated with bromine-water, it forms (A) 2-bromoaniline (B) 4-bromoaniline (C) mixture of 2 and 4-bromoaniline (D) 2,4,6-tribromoaniline

Tardigrade Admin · Accepted Answer

-NH2 groups activates the ring strongly, therefore, Br+ attack the benzene ring at 2, 4, 6 positions simultaneously. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-jokl1eqmvvf218qb.jpg" />

Q. When aniline is treated with bromine-water, it forms

2-bromoaniline

4-bromoaniline

mixture of 2 and 4-bromoaniline

2,4,6-tribromoaniline

$- N H_{2}$ groups activates the ring strongly, therefore, $B r^{+}$ attack the benzene ring at 2, 4, 6 positions simultaneously.

Q. When aniline is treated with bromine-water, it forms

2-bromoaniline

4-bromoaniline

mixture of 2 and 4-bromoaniline

2,4,6-tribromoaniline

−NH2​ groups activates the ring strongly, therefore, Br+ attack the benzene ring at 2, 4, 6 positions simultaneously.

$- N H_{2}$ groups activates the ring strongly, therefore, $B r^{+}$ attack the benzene ring at 2, 4, 6 positions simultaneously.