When an optically active amine (A) having molecular formula C4H11N is subjected to Hofmann’s exhaustive methylation followed by hydrolysis, an alkene (B) is produced which upon ozonolysis and subsequent hydrolysis yields formaldehyde and propanal. The amine ’A’ is

Question

When an optically active amine (A) having molecular formula C4H11N is subjected to Hofmann’s exhaustive methylation followed by hydrolysis, an alkene (B) is produced which upon ozonolysis and subsequent hydrolysis yields formaldehyde and propanal. The amine ’A’ is (A)  (B)  (C)  (D) CH3CH2CH2CH2NH2

Tardigrade Admin · Accepted Answer

The only optically active molecule is as shown. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/7356fec32a8d4047353ba880ed27466d-.png" />

Q. When an optically active amine $(A)$ having molecular formula $C_{4} H_{11} N$ is subjected to Hofmann’s exhaustive methylation followed by hydrolysis, an alkene $(B)$ is produced which upon ozonolysis and subsequent hydrolysis yields formaldehyde and propanal. The amine $’ A ’$ is

$C H_{3} C H_{2} C H_{2} C H_{2} N H_{2}$

The only optically active molecule is as shown.

Q. When an optically active amine (A) having molecular formula C4​H11​N is subjected to Hofmann’s exhaustive methylation followed by hydrolysis, an alkene (B) is produced which upon ozonolysis and subsequent hydrolysis yields formaldehyde and propanal. The amine ’A’ is

CH3​CH2​CH2​CH2​NH2​

The only optically active molecule is as shown.

Q. When an optically active amine $(A)$ having molecular formula $C_{4} H_{11} N$ is subjected to Hofmann’s exhaustive methylation followed by hydrolysis, an alkene $(B)$ is produced which upon ozonolysis and subsequent hydrolysis yields formaldehyde and propanal. The amine $’ A ’$ is

$C H_{3} C H_{2} C H_{2} C H_{2} N H_{2}$