Question

When acidified $K_{2}C{r}_2{O}_7$ solution is added to $S{n}^{2+}$ salts, then $S{n}^{2+}$ changes to

• A. $Sn$
• B. $S{n}^{3+}$
• C. $S{n}^{4+}$
• D. $S{n}^{+}$

Answer 1

Answer: (C)

$C{r}_2{O}_7^{2-}+14H^{+}+3S{n}^{2+}\to 2C{r}^{3+}+3S{n}^{4+}+7H_{2}O$