When a wave is reflected normally from a rigid boundary, the reflected wave suffers a phase change of (assuming no absorption)

Question

When a wave is reflected normally from a rigid boundary, the reflected wave suffers a phase change of (assuming no absorption) (A) π / 2 (B) π / 4 (C) π (D) 2 π

Tardigrade Admin · Accepted Answer

When a wave is incident normally on a rigid boundary, then assuming there is no absorption of energy by the boundary, the reflected wave has the same shape as the incident wave but it suffers a phase change of π or 180° on reflection. This is because the boundary is rigid and the disturbance must have zero displacement at all times at the boundary.

Q. When a wave is reflected normally from a rigid boundary, the reflected wave suffers a phase change of (assuming no absorption)

$π /2$

$π /4$

$π$

$2 π$

Q. When a wave is reflected normally from a rigid boundary, the reflected wave suffers a phase change of (assuming no absorption)

π/2

π/4

π

2π

$π /2$

$π /4$

$π$

$2 π$