When a rubber ball is taken to the bottom of a sea of depth 1400 m, its volume decreases by 2 %. The Bulk modulus of rubber ball is [density of water is 1 g cc and g=10 m / s 2 ]

Question

When a rubber ball is taken to the bottom of a sea of depth 1400 m, its volume decreases by 2 %. The Bulk modulus of rubber ball is [density of water is 1 g cc and g=10 m / s 2 ] (A) 7 × 108 N / m 2 (B) 6 × 108 N / m 2 (C) 14 × 108 N / m 2 (D) 9 × 106 N / m 2

Tardigrade Admin · Accepted Answer

Pressure at the bottom of sea =ρw g h =1000 kg / m 3 × 10 m / s 2 × 1400 m =14000000 N / m 2 Also we know (Δ V/V)=-(P/B) (Δ V/V)=(-2/100) (-2/100)=(-14000000/B) B=7 × 108 N / m 2

Q. When a rubber ball is taken to the bottom of a sea of depth $1400 m$ , its volume decreases by $2%$ . The Bulk modulus of rubber ball is [density of water is $1 g cc$ and $g = 10 m / s^{2}$ ]

$7 \times 1 0^{8} N / m^{2}$

$6 \times 1 0^{8} N / m^{2}$

$14 \times 1 0^{8} N / m^{2}$

$9 \times 1 0^{6} N / m^{2}$

Pressure at the bottom of sea $= ρ_{w} g h$
$= 1000 k g / m^{3} \times 10 m / s^{2} \times 1400 m$
$= 14000000 N / m^{2}$
Also we know
$\frac{Δ V}{V} = - \frac{P}{B}$
${\frac{Δ V}{V} = \frac{- 2}{100}}$
$\frac{- 2}{100} = \frac{- 14000000}{B}$
$B = 7 \times 1 0^{8} N / m^{2}$

Q. When a rubber ball is taken to the bottom of a sea of depth 1400m, its volume decreases by 2%. The Bulk modulus of rubber ball is [density of water is 1gcc and g=10m/s2 ]

7×108N/m2

6×108N/m2

14×108N/m2

9×106N/m2