When a motor cyclist moves in a circular track of radius 100 m , then the maximum velocity with which the cyclist can take the turn with leaning inwards is (Take coefficient of friction =0.2 T )

Question

When a motor cyclist moves in a circular track of radius 100 m , then the maximum velocity with which the cyclist can take the turn with leaning inwards is (Take coefficient of friction =0.2 T ) (A)  1.4 ms-1  (B)  14 ms-1  (C)  140 ms-1  (D)  280 ms-1

Tardigrade Admin · Accepted Answer

Maximum velocity, v=√μ rg =√0.2× 100× 10 =10√2=14 ms-1

Q. When a motor cyclist moves in a circular track of radius 100 m , then the maximum velocity with which the cyclist can take the turn with leaning inwards is (Take coefficient of friction $= 0.2 T$ )

$1.4 m s^{- 1}$

$14 m s^{- 1}$

$140 m s^{- 1}$

$280 m s^{- 1}$

Maximum velocity, $v = μ r g$ $= 0.2 \times 100 \times 10$ $= 102 = 14 m s^{- 1}$

Q. When a motor cyclist moves in a circular track of radius 100 m , then the maximum velocity with which the cyclist can take the turn with leaning inwards is (Take coefficient of friction =0.2T )

1.4ms−1

14ms−1

140ms−1

280ms−1