When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the …. Carbon atom,because

Question

When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the …. Carbon atom,because (A) D,the carbonyl group is drawn to the right (B) L, the carbonyl group is drawn to the left (C) acetal,it forms bond to an -OR and an - OR’ (D) anomeric, its substituents can assume an β or α position

Tardigrade Admin · Accepted Answer

When two cyclic forms of a carbohydrate differ in configuration only at hemiacetal carbons, they are said to be anomers. Thus, anomers are cyclic forms of carbohydrates that are epimeric at hemiacetal carbon and this carbon (C-1 of aldose) is called anomeric carbon, e.g.,

Q. When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the …. Carbon atom,because

D,the carbonyl group is drawn to the right

L, the carbonyl group is drawn to the left

acetal,it forms bond to an -OR and an - OR’

anomeric, its substituents can assume an $β$ or $α$ position

When two cyclic forms of a carbohydrate differ in configuration only at hemiacetal carbons, they are said to be anomers. Thus, anomers are cyclic forms of carbohydrates that are epimeric at hemiacetal carbon and this carbon ( $C - 1$ of aldose) is called anomeric carbon, e.g.,