When a diode is forward biased, it has a voltage drop of 0.5 V. The safe limit of current through the diode is 10 mA. If a battery of emf 1.5 V is used in the circuit, the value of minimum resistance to be connected in series with the diode so that the current does not exceed the safe limit is :

Question

When a diode is forward biased, it has a voltage drop of 0.5 V. The safe limit of current through the diode is 10 mA. If a battery of emf 1.5 V is used in the circuit, the value of minimum resistance to be connected in series with the diode so that the current does not exceed the safe limit is : (A) 100 Ω (B) 50 Ω (C) 300 Ω (D) 200 Ω

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/958f307e01bc1bf6cc25de6a289484d2-.png" /> 1.5-0.5- R × 10 × 10-3=0 ∴ R =100 Ω

$100Ω$

$50Ω$

$300Ω$

$200Ω$

$1.5 - 0.5 - R \times 10 \times 1 0^{- 3} = 0$
$∴ R = 100Ω$

Q. When a diode is forward biased, it has a voltage drop of 0.5V. The safe limit of current through the diode is 10mA. If a battery of emf 1.5V is used in the circuit, the value of minimum resistance to be connected in series with the diode so that the current does not exceed the safe limit is :

100Ω

50Ω

300Ω

200Ω

1.5−0.5−R×10×10−3=0 ∴R=100Ω

$100Ω$

$50Ω$

$300Ω$

$200Ω$

$1.5 - 0.5 - R \times 10 \times 1 0^{- 3} = 0$
$∴ R = 100Ω$