When a battery sends current through a resistance R1 for time t, the heat produced in the resistor is Q . When the same battery sends current through another resistance R 2 for time t, the heat produced in R 2 is again Q. Determine the internal resistance of battery:

Question

When a battery sends current through a resistance R1 for time t, the heat produced in the resistor is Q . When the same battery sends current through another resistance R 2 for time t, the heat produced in R 2 is again Q. Determine the internal resistance of battery: (A) r = R 1 R 2 (B) r =( R 1/ R 2) (C) r =√ R 1 R 2 (D) R 1=( R 2/ r )

Tardigrade Admin · Accepted Answer

A cell of given EMF internal resistance gives same power for two diff. resistances R 1 R 2 if R 1 R 2= r 2

Q. When a battery sends current through a resistance $R_{1}$ for time $t$ , the heat produced in the resistor is $Q .$ When the same battery sends current through another resistance $R_{2}$ for time $t$ , the heat produced in $R_{2}$ is again $Q$ . Determine the internal resistance of battery:

$r = R_{1} R_{2}$

$r = \frac{R _{1}}{R _{2}}$

$r = R_{1} R_{2}$

$R_{1} = \frac{R _{2}}{r}$

A cell of given EMF & internal resistance gives same power for two diff. resistances
$R_{1} &$ $R_{2}$ if $R_{1} R_{2} = r^{2}$

Q. When a battery sends current through a resistance R1​ for time t, the heat produced in the resistor is Q. When the same battery sends current through another resistance R2​ for time t, the heat produced in R2​ is again Q. Determine the internal resistance of battery:

r=R1​R2​

r=R2​R1​​

r=R1​R2​​

R1​=rR2​​

A cell of given EMF & internal resistance gives same power for two diff. resistances R1​& R2​ if R1​R2​=r2

Q. When a battery sends current through a resistance $R_{1}$ for time $t$ , the heat produced in the resistor is $Q .$ When the same battery sends current through another resistance $R_{2}$ for time $t$ , the heat produced in $R_{2}$ is again $Q$ . Determine the internal resistance of battery:

$r = R_{1} R_{2}$

$r = \frac{R _{1}}{R _{2}}$

$r = R_{1} R_{2}$

$R_{1} = \frac{R _{2}}{r}$

A cell of given EMF & internal resistance gives same power for two diff. resistances
$R_{1} &$ $R_{2}$ if $R_{1} R_{2} = r^{2}$