When 92U235 undergoes fission, 0.1% its original mass is changed into energy. How much energy is released if 1 kg of 92U235 undergoes fission?

Question

When 92U235 undergoes fission, 0.1% its original mass is changed into energy. How much energy is released if 1 kg of 92U235 undergoes fission? (A)  9× 1010J  (B)  9× 1011J  (C)  9× 1012J  (D)  9× 1013J

Tardigrade Admin · Accepted Answer

From the mass energy equivalence of Einstein E=Δ mc2 Here: Δ m=(0.1/100)=10-3kg So, E=10-3× (3× 108)2=9× 1013J

Q. When $_{92} U^{235}$ undergoes fission, 0.1% its original mass is changed into energy. How much energy is released if 1 kg of $_{92} U^{235}$ undergoes fission?

$9 \times 10^{10} J$

$9 \times 10^{11} J$

$9 \times 10^{12} J$

$9 \times 10^{13} J$

From the mass energy equivalence of Einstein $E = Δ m c^{2}$ Here: $Δ m = \frac{0.1}{100} = 10^{- 3} k g$ So, $E = 10^{- 3} \times (3 \times 10^{8})^{2} = 9 \times 10^{13} J$

Q. When 92​U235 undergoes fission, 0.1% its original mass is changed into energy. How much energy is released if 1 kg of 92​U235 undergoes fission?

9×1010J

9×1011J

9×1012J

9×1013J