When 92 U 235 is bombarded with one neutron, fission occurs and the products are three neutrons, 36 Kr 94, and

Question

When 92 U 235 is bombarded with one neutron, fission occurs and the products are three neutrons, 36 Kr 94, and (A)  56 Ba 141 (B) 54 Xe 139 (C)  56 Ba 139 (D)  58 I 142

Tardigrade Admin · Accepted Answer

When a slow neutron strikes a U235 nucleus it is absorbed by the nucleus and the following reaction occurs. 92 U 235+ 0 n1 arrow 36 Kr 94+ 56 Ba 139+30 n1+ text energy Hence, 56 B a139 is another product.

Q. When $_{92} U^{235}$ is bombarded with one neutron, fission occurs and the products are three neutrons, $_{36} K r^{94}$ , and

$_{56} B a^{141}$

$_{54} X e^{139}$

$_{56} B a^{139}$

$_{58} I^{142}$

When a slow neutron strikes a $U^{235}$ nucleus it is absorbed by the nucleus and the following reaction occurs.
$_{92} U^{235} +_{0} n^{1} \to_{36} K r^{94} +_{56} B a^{139} + 3_{0} n^{1} + energy$
Hence, $_{56} B a^{139}$ is another product.

Q. When 92​U235 is bombarded with one neutron, fission occurs and the products are three neutrons, 36​Kr94, and

56​Ba141

54​Xe139

56​Ba139

58​I142