When 92 U235 is bombarded with one neutron, fission occurs and the products are three neutrons, 36 mathrmKr94 , and

Question

When 92 U235 is bombarded with one neutron, fission occurs and the products are three neutrons, 36 mathrmKr94 , and (A)  56 mathrmBa141 (B)  54 mathrmXe139 (C)  56 mathrmBa139 (D)  58 mathrmI142

Tardigrade Admin · Accepted Answer

When a slow neutron strikes a U235 nucleus it is absorbed by the nucleus and the following reaction occurs. 92 mathrmU235+ 0 n1 arrow 36 mathrmKr94+ 56 mathrmBa139+3 0 n1+ energy Hence, 56 B a139 is another product.

Q. When $_{92} U^{235}$ is bombarded with one neutron, fission occurs and the products are three neutrons, $_{36} Kr^{94}$ , and

$_{56} Ba^{141}$

$_{54} Xe^{139}$

$_{56} Ba^{139}$

$_{58} I^{142}$

When a slow neutron strikes a $U^{235}$ nucleus it is absorbed by the nucleus and the following reaction occurs.
$_{92} U^{235} +_{0} n^{1} \to_{36} Kr^{94} +_{56} Ba^{139} + 3_{0} n^{1} +$ energy
Hence, $_{56} B a^{139}$ is another product.

Q. When 92​U235 is bombarded with one neutron, fission occurs and the products are three neutrons, 36​Kr94 , and

56​Ba141

54​Xe139

56​Ba139

58​I142