When 9.65 ampere current was passed for 1.0 hour into nitrobenzene in acidic medium, the amount of p- aminophenol produced is: (molar mass of p- aminophenol =109 g/mole )

Question

When 9.65 ampere current was passed for 1.0 hour into nitrobenzene in acidic medium, the amount of p- aminophenol produced is: (molar mass of p- aminophenol =109 g/mole ) (A) 10.9 g (B) 98.1 g (C) 109.0 g (D) 9.81 g

Tardigrade Admin · Accepted Answer

Moles of e-=(9 . 65 × 3600/96500)=0.36 4 moles e- reduce 1 mole nitrobenzene 0.36 moles e- reduce arrow 0.09 mole nitrobenzene Mass =0.09× 109 =9.81 g

Q. When $9.65$ ampere current was passed for $1.0$ hour into nitrobenzene in acidic medium, the amount of $p -$ aminophenol produced is :
(molar mass of $p -$ aminophenol $= 109 g / m o l e$ )

$10.9 g$

$98.1 g$

$109.0 g$

$9.81 g$

Moles of $e^{-} = \frac{9.65 \times 3600}{96500} = 0.36$
$4$ moles $e^{-}$ reduce $1$ mole nitrobenzene
$0.36$ moles $e^{-}$ reduce $\to 0.09$ mole nitrobenzene
Mass $= 0.09 \times 109$
$= 9.81 g$

Q. When 9.65 ampere current was passed for 1.0 hour into nitrobenzene in acidic medium, the amount of p− aminophenol produced is : (molar mass of p− aminophenol =109g/mole )

10.9g

98.1g

109.0g

9.81g