When 5 moles of He gas expand isothermally and reversibly at 300 K from 10 litre to 20 litre, the magnitude of the maximum work obtained is J. [nearest integer] (Given: R =8.3 J K -1 mol -1 and log 2=0.3010 )

Question

When 5 moles of He gas expand isothermally and reversibly at 300 K from 10 litre to 20 litre, the magnitude of the maximum work obtained is J. [nearest integer] (Given: R =8.3 J K -1 mol -1 and log 2=0.3010 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

n =5 mol T =300 K V 1=10 L V 2=20 L w =- nRT ℓ n ( V 2/ V 1) =-5 × 8.3 × 300 × ℓ n (20/10) =-8630.38 J

Q. When $5$ moles of $He$ gas expand isothermally and reversibly at $300 K$ from $10$ litre to $20$ litre, the magnitude of the maximum work obtained is ___ $J$ . [nearest integer] (Given: $R = 8.3 J K^{- 1} m o l^{- 1}$ and $lo g 2 = 0.3010$ )

$n = 5 m o l$
$T = 300 K$
$V_{1} = 10 L$
$V_{2} = 20 L$
$w = - n RT ℓ n \frac{V _{2}}{V _{1}}$
$= - 5 \times 8.3 \times 300 \times ℓ n \frac{20}{10}$
$= - 8630.38 J$

Q. When 5 moles of He gas expand isothermally and reversibly at 300K from 10 litre to 20 litre, the magnitude of the maximum work obtained is ___J. [nearest integer] (Given: R=8.3JK−1mol−1 and log2=0.3010 )

n=5mol T=300K V1​=10L V2​=20L w=−nRTℓnV1​V2​​ =−5×8.3×300×ℓn1020​ =−8630.38J

Q. When $5$ moles of $He$ gas expand isothermally and reversibly at $300 K$ from $10$ litre to $20$ litre, the magnitude of the maximum work obtained is ___ $J$ . [nearest integer] (Given: $R = 8.3 J K^{- 1} m o l^{- 1}$ and $lo g 2 = 0.3010$ )

$n = 5 m o l$
$T = 300 K$
$V_{1} = 10 L$
$V_{2} = 20 L$
$w = - n RT ℓ n \frac{V _{2}}{V _{1}}$
$= - 5 \times 8.3 \times 300 \times ℓ n \frac{20}{10}$
$= - 8630.38 J$